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MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    The de-Broglie wavelength of an electron having 80 eV of energy is nearly (\[1eV=1.6\times {{10}^{-19}}J,\]mass of electron \[=9.1\times {{10}^{-31}}kg,\] Planck's constant\[=6.6\times {{10}^{-34}}kg,s\])

    A) \[140{AA}\]                                     

    B)  \[0.14{AA}\]

    C) \[14{AA}\]                                        

    D)  \[1.4{AA}\]

    Correct Answer: D

    Solution :

    \[\lambda =\frac{h}{\sqrt{2mE}}\] \[=\frac{6.6\times {{10}^{-34}}}{\sqrt{2\times 9.1\times {{10}^{-31}}\times 80\times 1.6\times {{10}^{-19}}}}\] \[=1.4{\AA}\]


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