A) 140 m/s
B) 300 m/s
C) 1400 m/s
D) 5000 m/s
Correct Answer: C
Solution :
Bulk modulus \[K=\frac{\Delta p}{\frac{\Delta V}{V}}=\frac{100\times {{10}^{3}}}{0.005/100}=2\times {{10}^{9}}Pa\] Speed\[v=\sqrt{\frac{K}{d}}=\sqrt{\frac{2\times {{10}^{9}}}{{{10}^{3}}}}=\sqrt{2}\times {{10}^{3}}\] \[\Rightarrow \] \[v=1.400\times {{10}^{3}}=1400\,m/s\]
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