A) 4500 J
B) 90 J
C) 910 J
D) 0.45J
Correct Answer: D
Solution :
d) KE of rotation \[=\frac{1}{2}I{{\omega }^{2}}=\frac{1}{2}\times \left( \frac{2}{5}M{{R}^{2}} \right){{\omega }^{2}}\] \[KE=\frac{1}{5}M{{R}^{2}}{{\omega }^{2}}\] \[=\frac{1}{5}\times 1\times {{(3\times {{10}^{-2}})}^{2}}\times {{(50)}^{2}}\] \[=\frac{1}{5}\times 9\times {{10}^{-4}}\times 2500\] \[=0.45J\]
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