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MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    If at the same temperature and pressure, the densities of two diatomic gases are \[{{d}_{1}}\] and \[{{d}_{2}}\] respectively, the ratio of mean kinetic energy per molecule of gases will be

    A)  \[1:1\]                                 

    B)  \[{{d}_{1}}:{{d}_{2}}\]

    C)  \[\sqrt{{{d}_{1}}}:\sqrt{{{d}_{2}}}\]                       

    D)  \[\sqrt{{{d}_{2}}}:\sqrt{{{d}_{1}}}\]

    Correct Answer: A

    Solution :

                     Mean kinetic energy\[KE=\frac{3}{2}RT\]is independent of density. \[\therefore \]Ratio\[=1:1\]


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