A) 20 cm of Hg
B) 30 cm of Hg
C) 40 cm of Hg
D) 60 cm of Hg
Correct Answer: C
Solution :
At constant temperature \[{{p}_{1}}{{V}_{1}}={{p}_{2}}{{V}_{2}}\] \[\Rightarrow \]\[{{p}_{2}}=\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right){{p}_{1}}\] \[\Rightarrow \]\[{{p}_{2}}=\frac{0.1}{(0.1+0.09)}\times 76\,cm\,of\,Hg\] \[\Rightarrow \]\[{{p}_{2}}=40\,cm\,of\,Hg\]
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