A) \[50\sqrt{3}m/s\]
B) \[9.3m/s\]
C) \[6.6m/s\]
D) \[5.4m/s\]
Correct Answer: B
Solution :
\[\tan \theta =\frac{{{a}_{t}}}{{{a}_{c}}}=\frac{{{a}_{t}}}{{{v}^{2}}/r}\] \[\Rightarrow \] \[{{v}^{2}}=\frac{{{a}_{t}}r}{\tan \theta }\] \[=\frac{10\times 5}{\tan {{30}^{o}}}=\frac{10\times 5}{1/\sqrt{3}}\] \[{{v}^{2}}=50\times \sqrt{3}\] \[=50\times 1.732=86.6\] \[v=\sqrt{86.6}=9.3\,m/s\]
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