A) n = 1 to n =2
B) n =2 to n=6
C) n = 2to n =1
D) n= 6 to n=2
Correct Answer: C
Solution :
When transition is from upper state to lower state, the energy is evolved. Therefore, options and are practicable In option \[E=-Rch\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right]=-\frac{3}{4}Rch\] In option \[E=-Rch\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{6}^{2}}} \right)\] \[=-\frac{2}{9}Rhc\] Thus, maximum energy is evolved in option .
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