A) \[2CO(g)+{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g)\]
B) \[PC{{l}_{5}}(g)\xrightarrow{{}}PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]
C) \[{{H}_{2}}(g)+B{{r}_{2}}(g)\xrightarrow{{}}2HBr(g)\]
D) \[C(s)+2{{H}_{2}}O(g)\xrightarrow{{}}2{{H}_{2}}(g)+C{{O}_{2}}(g)\]
Correct Answer: C
Solution :
\[\Delta H=\Delta E+\Delta {{n}_{g}}RT\] For reaction\[{{H}_{2}}(g)+B{{r}_{2}}(g)\xrightarrow{{}}2HBr(g)\] \[\Delta {{n}_{g}}=0,\]while for other\[\Delta {{n}_{g}}\ne 0\] Thus, \[\Delta H=\Delta E+0\times RT\] \[\Delta H-\Delta E=0\]
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