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MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    The difference between heat of reaction at constant pressure and constant volume of the reaction \[2{{C}_{6}}{{H}_{6}}(l)+15{{O}_{2}}(g)\xrightarrow{{}}12C{{O}_{2}}(g)\] \[+6{{H}_{2}}O(l)\]at\[25{}^\circ C\](in kJ) is

    A) \[-7.43\]                              

    B) \[3.72\]

    C) \[-3.72\]                              

    D) \[7.43\]

    Correct Answer: A

    Solution :

                    \[\Rightarrow \]\[\Delta H=\Delta E+\Delta {{n}_{g}}RT\] \[\therefore \]  \[\Delta H-\Delta E=\Delta {{n}_{g}}RT\] \[=-3\times 8.314\times {{10}^{-3}}\times 298=-7.43\text{ }kJ\]


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