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MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    A metal wire of length \[l\] area of cross-section A and Young's modulus Y behaves as a spring of spring constant k given by

    A)  \[k=\frac{YA}{l}\]                           

    B)  \[k=\frac{2YA}{l}\]

    C)  \[k=\frac{YA}{2l}\]                         

    D)  \[k=\frac{Yl}{A}\]

    Correct Answer: A

    Solution :

                     \[Y=\frac{F/A}{\Delta l/l}\] \[\Rightarrow \]               \[F=YA\frac{\Delta l}{l}\]                                               ...(i) If\[k\]is spring constant, \[F=k\Delta l\]           ... (ii) Comparing Eqs. (i) and (ii), we get \[k=\frac{YA}{l}\]


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