A) 4.16J/cal
B) 4.18J/cal
C) 4.20J/cal
D) 4.22 J/cal
Correct Answer: C
Solution :
We know that \[{{C}_{p}}-{{C}_{v}}=\frac{R}{J}\] \[\Rightarrow \] \[J=\frac{R}{{{C}_{p}}-{{C}_{v}}}\] \[{{C}_{p}}-{{C}_{v}}=1.98\frac{cal}{g-mol-K}\] \[R=8.32\frac{J}{g-mol-K}\] \[J=\frac{8.32}{1.98}=4.20J/cal\]You need to login to perform this action.
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