A) 8rad/s
B) 4rad/s
C) 2 rad/s
D) 1 rad/s
Correct Answer: B
Solution :
Centripetal force = breaking force \[\Rightarrow \]\[m{{\omega }^{2}}r=\]breaking stress x cross-sectional area \[\Rightarrow \] \[m{{\omega }^{2}}r=P\times A\] \[\Rightarrow \] \[\omega =\sqrt{\frac{P\times A}{mr}}\] \[=\sqrt{\frac{4.8\times {{10}^{7}}\times {{10}^{-6}}}{10\times 0.3}}\] \[\omega =4\,rad/s\]You need to login to perform this action.
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