MGIMS WARDHA MGIMS WARDHA Solved Paper-2008

  • question_answer
    A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns/cm length. A current of 5 A falls through it. The magnetic field at the axis inside the solenoid is

    A) \[2\pi \times {{10}^{-3}}T\]                         

    B) \[2\pi \times {{10}^{-5}}T\]

    C) \[4\pi \times {{10}^{-2}}T\]                         

    D) \[4\pi \times {{10}^{-3}}T\]

    Correct Answer: A

    Solution :

    Magnetic field at the axis inside the solenoid \[B={{\mu }_{0}}ni\] Here,\[n=10\text{ }turns/cm=1000\text{ }turns/m,\text{ }i=5\text{ }A\] \[\therefore \]  \[B=4\pi \times {{10}^{-7}}\times 1000\times 5\] \[=2\pi \times {{10}^{-3}}T\].


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