A) \[Fe\]
B) \[{{O}_{2}}\]
C) \[Zn\]
D) \[{{H}^{+}}\]
Correct Answer: D
Solution :
Iron is rusted in presence of oxygen and moisture. \[\underset{moisture}{\mathop{{{H}_{2}}O}}\,+\underset{air}{\mathop{C{{O}_{2}}}}\,\xrightarrow{{}}{{H}_{2}}C{{O}_{3}}\] At anode \[{{H}_{2}}C{{O}_{3}}2{{H}^{+}}+CO_{3}^{2-}\] \[Fe\xrightarrow{{}}F{{e}^{2+}}+2{{e}^{-}}\] \[4F{{e}^{2+}}+{{O}_{2}}+4{{H}_{2}}O\xrightarrow{{}}F{{e}_{2}}{{O}_{3}}+8{{H}^{+}}\] At cathode \[{{H}^{+}}+{{e}^{-}}\xrightarrow{{}}H\] \[4H+{{O}_{2}}\xrightarrow{{}}2{{H}_{2}}O\] Hence, rusting of iron is catalysed by hydrogen ion
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