A) \[5\times {{10}^{16}}Hz\]
B) \[0.5\times {{10}^{27}}Hz\]
C) \[0.5\times {{10}^{18}}Hz\]
D) \[5\times {{10}^{18}}Hz\]
Correct Answer: D
Solution :
\[E=m{{c}^{2}}\] \[E=hv\] \[m{{c}^{2}}=hv\] \[v=\frac{m{{c}^{2}}}{h}=\frac{1.1\times {{10}^{-23}}\times 3\times {{10}^{8}}}{6.6\times {{10}^{-34}}}\] \[=5\times {{10}^{18}}Hz\]
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