A) \[{{E}_{1}}>{{E}_{2}}\]
B) \[{{E}_{1}}={{E}_{2}}\]
C) \[{{E}_{1}}<{{E}_{2}}\]
D) cannot be said
Correct Answer: C
Solution :
\[{{I}_{1}}{{\omega }_{1}}={{I}_{2}}{{\omega }_{2}}\] \[\therefore \] \[\frac{{{\omega }_{1}}}{{{\omega }_{2}}}=\frac{{{I}_{2}}}{{{I}_{1}}}\] Now, \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{\frac{1}{2}{{I}_{1}}\omega _{1}^{2}}{\frac{1}{2}{{I}_{2}}\omega _{2}^{2}}\] \[=\frac{{{I}_{1}}}{{{I}_{2}}}\times {{\left( \frac{{{I}_{2}}}{{{I}_{1}}} \right)}^{2}}=\frac{{{I}_{2}}}{{{I}_{1}}}\] As \[{{I}_{1}}>{{I}_{2}}\] \[\therefore \] \[{{E}_{1}}<{{E}_{2}}\]
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