MGIMS WARDHA MGIMS WARDHA Solved Paper-2007

  • question_answer
    The angular amplitude of a simple pendulum is \[{{\theta }_{0.}}\] The maximum tension in its string will be

    A) \[mg(1-{{\theta }_{0}})\]                             

    B) \[mg(1+{{\theta }_{0}})\]

    C) \[mg(1-\theta \,_{0}^{2})\]                        

    D) \[mg(1+\theta \,_{0}^{2})\]

    Correct Answer: D

    Solution :

    \[{{T}_{\max }}=mg+\frac{m{{v}^{2}}}{l}\] \[=mg+\frac{2mg}{l}l(1-\cos {{\theta }_{0}})\] \[=mg+2mg\left[ 1-1+\frac{\theta _{0}^{2}}{2} \right]\] \[=mg(1+\theta _{0}^{2})\]


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