MGIMS WARDHA MGIMS WARDHA Solved Paper-2007

  • question_answer
    A panicle of mass 10 g is describing SHM along a straight line with period of 2 s and amplitude of 10 cm. Its kinetic energy when it is al 5 cm from its equilibrium position is

    A) \[3.75{{\pi }^{2}}\,erg\]                                

    B) \[375{{\pi }^{2}}\,erg\]

    C) \[0.375{{\pi }^{2}}\,erg\]             

    D) \[37.5{{\pi }^{2}}\,erg\]

    Correct Answer: B

    Solution :

    Kinetic Energy\[=\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{y}^{2}})\] \[KE=\frac{1}{2}\times 10\times {{\left( \frac{2\pi }{2} \right)}^{2}}\times ({{10}^{2}}-{{5}^{2}})\] \[KE=\frac{1}{2}\times 10\times \frac{4{{\pi }^{2}}}{4}\times (100-25)\] \[KE=375{{\pi }^{2}}\,erg\]


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