A) \[1.2\times {{10}^{-4}}erg/nucleus\]
B) \[8.2\times {{10}^{-4}}erg/nucleus\]
C) \[10.2\times {{10}^{-4}}erg/nucleus\]
D) \[1.9\times {{10}^{-4}}erg/nucleus\]
Correct Answer: A
Solution :
\[1\text{ }amu=1.66\times {{10}^{-24}}g\] \[E=m{{c}^{2}}\] Here, m = mass \[c=velocity\text{ }of\text{ }light\text{ }(3\times {{10}^{10}}cm/s)\] \[=1.66\times {{10}^{-24}}g\times {{(3\times {{10}^{10}}cm/s)}^{2}}\] \[=1.49\times {{10}^{-3}}ergs\] Binding energy = mass defect\[\times E\] \[=1.2\times {{10}^{-4}}erg/nucleus\] Note: It is per nucleus and not per nucleon.
You need to login to perform this action.
You will be redirected in
3 sec
