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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    If equivalent conductance of 1M benzoic acid is\[12.8\text{ }oh{{m}^{-1}}c{{m}^{2}}\]and if the conductance of benzoate ion and\[{{H}^{+}}\]ion are 42 and 288.42\[oh{{m}^{-1}}c{{m}^{2}}\]respectively. Its degree of dissociation is:

    A)  39%                                      

    B)  3.9%

    C)   0.35%                                 

    D)  0.039%

    Correct Answer: B

    Solution :

                     We know \[\lambda _{{{C}_{6}}{{H}_{5}}COOH}^{\infty }=\lambda _{{{C}_{6}}{{H}_{5}}CO{{O}^{-}}}^{\infty }+\lambda _{{{H}^{+}}}^{\infty }\]                 \[=42+288.42\]                 \[=330.0.42\] Degree of dissociation\[\alpha =\frac{{{\lambda }_{v}}}{{{\lambda }_{\infty }}}=\frac{12.8}{330.42}\]                                 \[=0.039\times 100\]                                 \[=3.9%\]


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