A) increase of 59 mV
B) decrease of 59 mV
C) increase of 29.5 mV
D) decrease of 29.5 mV
Correct Answer: A
Solution :
We know; \[{{E}_{cell}}=\frac{0.059}{2}\log \frac{1}{C}\] where C = 100 times \[{{E}_{cell}}=-\frac{0.059}{2}\log \frac{1}{100}\] \[=-\frac{0.059}{2}\times -2\] \[0.059\text{ }V=59\text{ }mV\] Thus, if the\[Z{{n}^{2+}}/Zn\] electrode is diluted to 100 times than the emf is increase of 59 mV.
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