A) Curium
B) Californium
C) Uranium
D) Terbium
Correct Answer: D
Solution :
Terbium (Tb) is a lanthanide it belongs to\[4f\]series and electronic configuration is [Xe] \[4{{f}^{9}}5d{}^\circ \text{ }6{{s}^{2}},\] while curium (Cm) californium (Cf) and uranium (U) are all the actinides.
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