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MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    An electron accelerated through a potential difference enters into a uniform transverse magnetic field and experience a force F. If the accelerating potential is increased lo 2V, the           electron in the same magnetic field will experience a force :

    A) \[F\]                                     

    B)  \[F/2\]

    C) \[\sqrt{2}F\]                      

    D) \[F2\]

    Correct Answer: C

    Solution :

    \[\frac{1}{2}m{{v}^{2}}=eV\] \[\Rightarrow \]               \[v={{\left( \frac{2eV}{m} \right)}^{1/2}}\] Force      \[F=evB\]                 \[F=eB{{\left( \frac{2eV}{m} \right)}^{1/2}}\]                 \[F\propto \sqrt{V}\]                 \[\frac{{{F}_{2}}}{{{F}_{1}}}=\sqrt{\frac{{{V}_{2}}}{{{V}_{1}}}}\]                 \[=\sqrt{\frac{2V}{V}}\] \[\therefore \]  \[{{F}_{2}}=\sqrt{2}F\]


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