MGIMS WARDHA MGIMS WARDHA Solved Paper-2006

  • question_answer
    A ball falling freely from a height of 4.9 m/s hits 3 a horizontal surface. If \[e=\frac{3}{4},\] then the ball will 4 hit the surface second time after:

    A) 0.5s                                       

    B) 1.5s

    C)  3.5s                                      

    D)  3.4s

    Correct Answer: B

    Solution :

    Velocity on hitting the surface \[=\sqrt{2\times 9.8\times 4.9}\] \[=9.8m/s\] Velocity after first bounce \[v=\frac{3}{4}\times 9.8\] Time taken from first bounce to the second bounce \[=\frac{2v}{g}=2\times \frac{3}{4}\times 9.8\times \frac{1}{9.8}=1.5\,s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner