A) 40 MeV
B) 80 MeV
C) 20 MeV
D) 60 MeV
Correct Answer: B
Solution :
Maximum energy in cyclotron. \[E=\frac{1}{2}\frac{{{B}^{2}}{{q}^{2}}{{R}^{2}}}{m}\] where, \[R=\]radius of does of cyclotron. Here \[\frac{{{E}_{d}}}{{{E}_{p}}}={{\left( \frac{{{q}_{d}}}{{{q}_{p}}} \right)}^{2}}.\left( \frac{{{m}_{p}}}{{{m}_{d}}} \right)\] \[\frac{40}{{{E}_{p}}}={{\left( \frac{q}{q} \right)}^{2}}.\left( \frac{m}{2m} \right)\] \[{{E}_{p}}=80\,MeV\]
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