2. Solved Papers
  3. MGIMS WARDHA

MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    pH of a solution of 10 mL 1N sodium acetate and 50 mL 2N acetic acid\[({{K}_{a}}=1.8\times {{10}^{-5}}),\]is approximately:

    A)  4                                            

    B)  5

    C)  6                                            

    D)  7

    Correct Answer: A

    Solution :

                     Given,\[Ka=1.8\times {{10}^{-5}}\] [salt]\[=1\times 10=10\]millimol [Acid]\[=2\times 50=100\] millimol From Henderson's equation \[pH=pKa+\log \frac{[salt]}{[acid]}\]                 \[=-\log (1.8\times {{10}^{-5}})+\log \frac{10}{100}\]                 \[=-\log 1.8+5+\log {{10}^{-1}}\] \[=-0.2553+5-1=3.7447\] \[\approx 4\]


You need to login to perform this action.
You will be redirected in 3 sec spinner