A) \[C{{H}_{3}}C{{H}_{2}}OK\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}C{{H}_{2}}OC{{H}_{2}}C{{H}_{3}}\]
D) \[C{{H}_{2}}=C{{H}_{2}}\]
Correct Answer: D
Solution :
Alkyl halides undergoes\[\beta -\]elimination in presence of alcoholic KOH, to give unsaturated hydrocarbons. This is also called dehydrodehalogenation of alkyl halides. \[C{{H}_{3}}.C{{H}_{2}}Cl\xrightarrow{alc.\text{ }KOH}\underset{ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]\[+KCl+{{H}_{2}}O\]
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