A) 931.1 MeV
B) \[1.492\times {{10}^{13}}erg\]
C) 1000 J
D) 107 erg
Correct Answer: A
Solution :
From Einstein equation, \[E=m{{c}^{2}}\] \[\therefore \]Energy equivalent to 1 amu \[(E)=1\text{ }a.m.u.\times {{(3\times {{10}^{8}}m/s)}^{2}}\] \[=1.66\times {{10}^{-~27}}kg\times 9\times {{10}^{16}}{{m}^{2}}/{{s}^{2}}\] \[=14.94\times {{10}^{-11}}joule\] (kg\[{{m}^{2}}/{{s}^{2}}=\] joule) \[=\frac{14.94\times {{10}^{-11}}}{1.6\times {{10}^{-13}}}MeV\] \[=931.1\text{ }MeV\]
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