A) 250 ml solvent
B) 250 g solvent
C) 250 ml solution
D) 1000 ml solvent
Correct Answer: B
Solution :
We know that, \[Molality=\frac{no.\text{ }of\text{ }moles\text{ }of\text{ }solute}{weight\text{ }of\text{ }solvent\text{ }(in\text{ }kg)}\] \[\therefore \] \[2.0=\frac{0.5}{weight\,of\,solvent\,(in\,kg)}\] \[\therefore \]weight of solvent \[=\frac{0.5}{2.0}=0.250\,kg=250\,g\]
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