MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    87.5% decomposition of a radioactive substance complete in 3 hours. What is the half-life of that substance?

    A)  2 hours                               

    B)  3 hours

    C)  90 minutes                        

    D)  1 hours

    Correct Answer: D

    Solution :

                     Given, \[{{N}_{0}}=100,\text{ }N=100-87.5=12.5,\] \[t=3\,hours,\,{{t}_{1/2}}=?\] We know that   \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{\frac{t}{{{t}_{1/2}}}}}\] \[\frac{12.5}{100}={{\left( \frac{1}{2} \right)}^{3/{{t}_{1/2}}}}\] or                            \[{{\left( \frac{1}{2} \right)}^{3}}={{\left( \frac{1}{2} \right)}^{3/{{t}_{1/2}}}}\] Hence,                  \[\frac{3}{{{t}_{1/2}}}=3\] or     \[{{t}_{1/2}}=\frac{3}{3}=1\text{ }hour\]


You need to login to perform this action.
You will be redirected in 3 sec spinner