A) \[{{({{C}_{2}}{{H}_{5}})}_{2}}S{{O}_{4}}\]
B) \[C{{H}_{2}}=C{{H}_{2}}\]
C) \[C{{H}_{3}}COOH\]
D) \[{{C}_{2}}{{H}_{5}}HS{{O}_{4}}\]
Correct Answer: B
Solution :
Ethyl alcohol, on heating at\[165{}^\circ -170{}^\circ C\]with cone.\[{{N}_{2}}S{{O}_{4}},\]gives ethylene. \[{{C}_{2}}{{H}_{5}}OH\xrightarrow[{{170}^{o}}C]{cone.\text{ }{{H}_{2}}S{{0}_{4}}}\underset{ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\] \[+{{H}_{2}}O\]
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