A) \[C{{F}_{2}}=C{{F}_{2}}\]
B) \[C{{F}_{2}}=CC{{l}_{2}}\]
C) \[C{{H}_{2}}FC{{H}_{2}}F\]
D) \[C{{F}_{2}}=CFCl\]
Correct Answer: A
Solution :
Teflon is a polymer of tetra fluoro ethylene \[\underset{tetra\text{ }fluoro\text{ }ethylene}{\mathop{nC{{F}_{2}}=C{{F}_{2}}}}\,\xrightarrow{polymerisation}\]\[\underset{Teflon}{\mathop{{{[-C{{F}_{2}}-C{{F}_{2}}-]}_{n}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
