A) ammonical\[AgN{{O}_{3}}\]
B) \[\frac{B{{r}_{2}}}{CC{{l}_{4}}}\]
C) alkaline\[KMn{{O}_{4}}\]
D) aqueous\[B{{r}_{2}}\]
Correct Answer: A
Solution :
Ammonical\[AgN{{O}_{3}}\]reacts only with propyne to give white precipitate, while propene does not react with it. \[C{{H}_{3}}-C\equiv CH+AgN{{O}_{3}}+N{{H}_{4}}OH\]\[\xrightarrow{{}}C{{H}_{3}}-\underset{white}{\mathop{C\equiv }}\,CAg\downarrow +N{{H}_{4}}N{{O}_{3}}+{{H}_{2}}O\]
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