A) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}\]
B) \[BrC{{H}_{2}}CH=C{{H}_{2}}\]
C) \[BrC{{H}_{2}}CH=CHBr\]
D) \[BrC{{H}_{2}}\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,=CHBr\]
Correct Answer: B
Solution :
Propene reacts with N-bromo succinimide to give allyl bromide, as the allyl hydrogen is comparatively easier to be replaced than vinyl hydrogen.
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