A) 6.83 m/s2
B) 8 m/s2
C) 5.31 m/s2
D) 4 m/s2
Correct Answer: C
Solution :
The car will experience two types of accelerations (i) Radial acceleration due to circular path \[{{a}_{r}}=\frac{{{\upsilon }^{2}}}{r}\] \[=\frac{{{(30)}^{2}}}{500}=1.8\,m/{{s}^{2}}\] (ii) Tangential acceleration due to tangential speed \[{{a}_{T}}=\left( \frac{\Delta \upsilon }{\Delta T} \right)=5\,\,m/{{s}^{2}}\] Therefore, resultant acceleration \[a=\sqrt{a_{r}^{2}+a_{T}^{2}}\] \[=\sqrt{{{(1.8)}^{2}}+{{(5)}^{2}}}\] \[=\sqrt{28.24}=5.31\,m/{{s}^{2}}\]
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