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MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    The magnification of an astronomical telescope is 10 and the focal length of eye-piece is 20 cm. The focal length of objective lens is :

    A) \[\frac{1}{200}\] cm                       

    B) 2 cm

    C) 200 cm                                 

    D) 100 cm

    Correct Answer: C

    Solution :

    Magnification of astronomical telescope \[m=\frac{{{f}_{0}}}{20}\]where\[{{f}_{o}}=\]focal length of objective lens \[{{f}_{e}}=\]focal length of eye piece \[\therefore \]  \[10=\frac{{{f}_{o}}}{20}\] \[\Rightarrow \]               \[{{f}_{o}}=10\times 20\] \[\Rightarrow \]               \[{{f}_{o}}=200\,cm\]


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