A) \[2\times {{10}^{-1}}T\]
B) \[4.31\times {{10}^{-2}}T\]
C) \[6.28\times {{10}^{-4}}T\]
D) \[9.81\times {{10}^{-4}}T\]
Correct Answer: C
Solution :
Magnetic field at the centre of the coil \[B={{10}^{-7}}\times \frac{2\pi ni}{r}\] Here: \[n=1000,\text{ }r=0.1\text{ }m,\text{ }i=0.1\text{ }A\] \[\therefore \] \[B=\frac{{{10}^{-7}}\times 2\times 3.14\times 1000\times 0.1}{0.1}\] \[=6.28\times {{10}^{-4}}\]Tesla
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