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MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    The momentum of two masses \[{{m}_{1}}\]and \[{{m}_{2}}\]are same. The ratio of their kinetic energies \[{{E}_{1}}\] and \[{{E}_{2}}\] is:            

    A) \[\sqrt{{{m}_{1}}}:\sqrt{{{m}_{2}}}\]                      

    B) \[{{m}_{1}}:{{m}_{2}}\]

    C) \[{{m}_{2}}:{{m}_{1}}\]                                

    D) \[m_{1}^{2}:m_{2}^{2}\]

    Correct Answer: C

    Solution :

    Momentum of first body = momentum of second body\[=m\upsilon \] \[\therefore \]  \[E=\frac{1}{2}m{{\upsilon }^{2}}\]                 \[=\frac{1}{2m}{{(m\upsilon )}^{2}}\] Hence,    \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}}\]


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