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MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    A block of mass 1 kg is placed on the wall under a force F. If coefficient of L   friction \[(\mu )\] is 0.5, then minimum value F  of force applied is :

    A) 9.8 N                                     

    B) 49 N

    C) 19.6 N                                  

    D) 1.96 N

    Correct Answer: C

    Solution :

    Weight of block\[=mg\] For block to be balanced, \[mg=\mu F\] \[\therefore \]  \[F=\frac{mg}{\mu }\]                 \[=\frac{1\times 9.8}{0.5}=19.6\,N\]


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