MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    Magnetic and electric field are acting on a proton moving with velocity \[\upsilon .\] Proton will be undefeated if:

    A) E is parallel to \[\upsilon .\] but perpendicular to B

    B) E and B both are parallel to \[\upsilon .\]

    C)  E and B are perpendicular to each other

    D) E B and v are perpendicular to one another and \[\upsilon =\frac{E}{B}\]

    Correct Answer: D

    Solution :

    Since, proton is undecflected, therefore net force on it is zero \[F=q\overrightarrow{E}+q(\overrightarrow{v}\times \overrightarrow{B})=0\]                 \[=q\overrightarrow{E}=-q(\overrightarrow{v}\times \overrightarrow{B})\]In this condition, E, B and\[\upsilon \]are perpendicular to one another


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