A) doubled
B) halved
C) quadrupled
D) unchanged
Correct Answer: B
Solution :
From Wein's displacement law, \[{{\lambda }_{m}}T=cons\tan t\] \[\Rightarrow \] \[{{\lambda }_{m}}T=\lambda {{'}_{m}}T\] \[\Rightarrow \] \[\lambda {{'}_{m}}=\frac{{{\lambda }_{m}}T}{T'}\] \[\Rightarrow \] \[\lambda {{'}_{m}}=\frac{{{\lambda }_{m}}T}{2T}\] \[\therefore \] \[\lambda {{'}_{m}}=\frac{{{\lambda }_{m}}}{2}\] Hence, wavelength will be halved
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