MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    A car covers 2/5 of a certain distance with speed \[{{\upsilon }_{1}}\] and rest 3/5 part with velocity \[{{\upsilon }_{2.}}\] The average speed of the car is:

    A) \[\frac{1}{2}\sqrt{{{\upsilon }_{1}}{{\upsilon }_{2}}}\]                                    

    B) \[\frac{5{{\upsilon }_{1}}{{\upsilon }_{1}}}{3{{\upsilon }_{1}}+2{{\upsilon }_{2}}}\]

    C) \[\frac{2{{\upsilon }_{1}}{{\upsilon }_{2}}}{{{\upsilon }_{1}}+{{\upsilon }_{2}}}\]                                

    D) \[\frac{{{\upsilon }_{1}}+{{\upsilon }_{2}}}{2}\]

    Correct Answer: A

    Solution :

    Let total distance covered \[=s\] \[{{t}_{1}}=\frac{(2/5)s}{{{\upsilon }_{1}}}\]and \[{{t}_{2}}=\frac{(3/5)s}{{{\upsilon }_{2}}}\] \[Average\text{ }speed=\frac{total\text{ }distance}{total\text{ }time}\] \[\upsilon =\frac{s}{{{t}_{1}}+{{t}_{2}}}\] Or           \[\upsilon =\frac{s}{\frac{2s}{5{{\upsilon }_{1}}}+\frac{3s}{5{{\upsilon }_{2}}}}\] Hence,     \[\upsilon =\frac{5{{\upsilon }_{1}}{{\upsilon }_{2}}}{2{{\upsilon }_{2}}+3{{\upsilon }_{1}}}\]


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