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MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    36 g water and 828 g ethyl alcohol form an ideal solution. The mole fraction of water in it, is:

    A)  1.0                                        

    B)  0.7

    C)  0.4                                        

    D)  0.1

    Correct Answer: D

    Solution :

                     Number of moles of water \[(n)=\frac{36}{18}=2\] No. of moles of ethyl alcohol \[(N)=\frac{828}{46}=18\] \[\therefore \]  Mole-fraction of water                                 \[=\frac{n}{n+N}\]                                 \[=\frac{2}{2+18}=\frac{2}{20}=0.1\]


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