MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    For a gaseous reaction,\[{{C}_{2}}{{H}_{4}}+{{H}_{2}}{{C}_{6}}{{H}_{6}};\]                    \[\Delta H=-32.7\text{ }kcal.\] The concentration of\[{{C}_{2}}{{H}_{4}}\]can be decreased by:

    A)  increasing pressure

    B)  increasing amount of\[{{H}_{2}}\]

    C)  decreasing temperature

    D)  all of these

    Correct Answer: D

    Solution :

                     \[{{C}_{2}}{{H}_{5}}+{{H}_{2}}{{C}_{2}}{{H}_{6}}+32.7\,kcal\] In this reaction, volume is decreasing and heat is evolving. Hence, according to Le-Chatelier principle, we have to increase pressure, decrease temperature and increase concentration of\[{{H}_{2}}\]to make the reaction proceed in forward direction.


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