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Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    \[{{C}_{60}}\](bucky ball) is cubic closest packed (face centred cubic) in its crystalline form. If you insert potassium atoms into all the tetrahedral and octahedral holes of the \[{{C}_{60}}\]structure, the formula would become\[{{K}_{x}}{{C}_{60}}\]. What is the value of x?

    A) 1                                                

    B) 2

    C) 3                                

    D) None of these

    Correct Answer: C

    Solution :

    In fee crystal system, there will be \[^{4}{{C}_{60}}\] and 12 K (8 in tetrahedral voids and 4 in octahedral voids). Hence, formula will be \[{{K}_{12}}{{C}_{60\times 4}}={{K}_{3}}{{C}_{60}}\,i.e,x=3\]


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