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Manipal Medical Manipal Medical Solved Paper-2013

  • question_answer
    A hypothetical experiment conducted to determine Youngs formula\[Y=\frac{\cos \theta {{T}^{x}}.\tau }{{{l}^{3}}}\]. If Y = Youngs modulus, T = time period, t = Torque and\[l=\]length, then find the value of \[x\].

    A)  zero     

    B)  1        

    C)  2        

    D)  3

    Correct Answer: A

    Solution :

     \[y=\frac{\cos \theta {{T}^{x}}.\tau }{{{l}^{3}}}\] \[[y]=[M{{L}^{-1}}{{T}^{-2}}][T]=[{{T}^{2}}]\] \[[T]=[M{{L}^{2}}{{T}^{-2}}]\] \[\theta =\]dimensionless \[(l)=[L]\] \[[M{{L}^{-1}}{{T}^{-2}}]=\frac{{{[T]}^{x}}[M{{L}^{2}}{{T}^{-2}}]}{[{{L}^{3}}]}\] omparing the power, \[-2+x=-2\] \[x=0\]


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