A) Stephens reduction
B) Cannizzaros reaction
C) Clemmensen reduction
D) Rosenmunds reduction
Correct Answer: A
Solution :
In the Stephens reduction alkyl cyanide is reduced to aldehyde by\[SnC{{l}_{2}}/HCl\]. \[R=C\equiv N+2H\xrightarrow[{}]{SnC{{l}_{2}}/HCl}\underset{alidime\text{ }hydrochloride}{\mathop{RCH=NH.HCl}}\,\] \[\xrightarrow[{}]{{{H}_{2}}O}\underset{aldehyde}{\mathop{RCHO}}\,+N{{H}_{4}}Cl\]
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