A) \[{{F}_{2}}\]
B) \[{{H}_{2}}\]
C) \[{{N}_{2}}\]
D) \[{{O}_{2}}\]
Correct Answer: B
Solution :
\[H_{2}^{+}=\sigma 1{{s}^{1}}\]According to molecular orbital theory) Bond order \[=\frac{bonding\text{ }electrons-antibonding\text{ }electrons}{2}\] \[=\frac{1}{2}=0.5\] \[H_{2}^{+}\]is paramagnetic due to the presence of one unpaired electron.
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