A) \[5\times {{10}^{-2}}m/s\]
B) \[0.5\text{ }m/s\]
C) \[5\times {{10}^{-3}}\text{ }m/s\]
D) \[5\times {{10}^{-6}}\text{ }m/s\]
Correct Answer: C
Solution :
The current i crossing area of cross-section A, can be expressed in terms of drift velocity\[{{v}_{d}}\]and the moving charges as \[i=ne{{v}_{d}}A\] where,\[n\] is number of charge carriers per unit volume and e the charge on the carrier. \[\therefore \]\[{{v}_{d}}=\frac{i}{neA}=\frac{24\times {{10}^{-3}}}{(3\times {{10}^{23}})(1.6\times {{10}^{-19}}){{(10)}^{-4}}}\] \[=5\times {{10}^{-3}}m/s\]
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