A) 200
B) 90.5
C) 100
D) 1.005
Correct Answer: A
Solution :
The relation between current gain of a common-base transistor\[(\alpha )\]to that of current gain between a common-emitter transistor\[(\beta )\]is \[\beta =\frac{\alpha }{1-\alpha }\] Given, \[\alpha =0.995\] \[\therefore \] \[\beta =\frac{0.995}{1-0.995}=199\approx 200\]
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